陶瓷厂家
免费服务热线

Free service

hotline

010-00000000
陶瓷厂家
热门搜索:
成功案例
当前位置:首页 > 成功案例

看一看:REI等值法用于多节点配电系统短路电流计

发布时间:2021-11-18 05:18:08 阅读: 来源:陶瓷厂家

中图分类号:TM 711 文献标识码:A文章编号:0258⑻013 (2000) 04-0064-05STUDIES ON APPLYING REI METHOD TO COMPUTING SHORT-CIRCUITFAULT CURRENT OF DISTRIBUTION SYSTEM OF MANY NODESSHAO Yu-huai LI Xiao-wei(Taiyuan University of Science and Technology,Taiyuan,030024 China)CHENG Jin-sheng(Shanxi Chemical Industry Designing Institute,Taiyuan 030024有贷款住房拆迁怎么办理,China)ABSTRACT:Applying the part hoed equivalent equation to power networks spread REI(Radial Equivalent Independent) network is researched.The application of REI(Radial Equivalent Independent) method to calculating short-circuit fault current of distribution system is presented in this paper,The power supply of external system is equivalently linked up boundry node.The boundary nodes is included in reserred node.The active node of original external system network is changed into passive node of equivalent network. The mathematical model for short-circuit fault current of distribution system is simplified.The calculation program of short-circuit fault current is more simple and direct and more practical.The precision of calculation is obviously risen.KEY WORDS:many nodes distribution system; short-circuit fault current calculation; Radial Equivalent Independent method 1 引言电力系统短路故障是1个复杂的电磁暂态进程,利用对称分量法分析计算3相对称电力系统的不对称短路或非对称断相故障时,总是将故障端口处3相不对称的支路阻抗参数等值转换成3个相互独立的正、负、零序3相对称的电流源,从而将难于求解的3相不对称故障的计算,转换成易于求解的3个相互独立而又对称的3相电路网络的计算。工程实用计算中,视各序网络为线性网络,如用下标(S)表示序列,n(S)为各序网络的独立节点数,利用对称分量法计算故障时,需解算独立节点数为n(S)的各序大型电路网络,计算工作量相当大。在很多情况下我们感兴趣的多是大型网络中的某个局部网络,其关联节点数r(S)远小于n(S),或为了加快故障的计算速度,或受所用计算机容量的限制,常常需要将大型网络节点方程缩减成预定节点数目的等值节点方程。本文提出了将REI等值法[1]用于多节点配电系统短路电流计算,对扩大的REI等值网络利用局部节点等值方程进行了研究,使多节点配电系统短路电流计算的数学模型得到简化,短路电流计算程序更简捷、实用拆迁款迟迟下不来怎么办。2 局部节点等值方程局部节点等值方程是将大型网络节点分为两大类:保存节点r(S)及消去节点e(S),e(S)=n(S)-r(S)。计算时,在各序网中先对保存节点编号,后对消去节点编号,则其节点导纳方程Y(S)U(S)=I(S)按保存节点、消去节点进行分块,可得 (1)式中 Y(S)为节点导纳矩阵;U(S)为节点电压列矢量;I(S)为节点注入电流列矢量;Yrr(S)包括保存节点的自导纳和互导纳;Yre(S)、Yer(S)为保存节点与消去节点之间的互导纳;Yee(S)包括消去节点的自导纳和互导纳;Ur(S)是保存节点电压列矢量;Ue(S)为消去节点电压列矢量;Ir(S)为保存节点注入电流列矢量;Ie(S)为消去节点注入电流列矢量。由于在等值缩减的前后,Ur(S)应保持不变,因此利用高斯消去法消去e(S)个节点后得保存节点的等值导纳方程为(Yrr(S)-Yre(S)Y-1ee(S)Yer(S))Ur(S)=Ir(S)-Yre(S)Y-1ee(S)Ie(S)(2)简记为 YNrr(S)Ur(S)=INr(S) (3)式中 YNrr(S)为保存节点的等值导纳矩阵;INr(S)为等值电流源[2]。YNrr(S)=Yrr(S)-Yre(S)Y-1ee(S)Yer(S) (4)INr(S)=Ir(S)-Yre(S)Y-1ee(S)Ie(S) (5)由式(4)和式(5)可知,当被消节点是有源节点,即Ie(S)不等于零时,则原网络Y(S)对应的保存节点的子块Yrr(S)及保存节点的电源Ir(S)均需修正;如被消节点是无源节点即Ie(S)等于零时,则勿需修正保存节点的电流源。实用工程计算中,故障前认为系统处于3相对称运行状态,所以负序网的Ie(2)、零序网的Ie(o)均为零。如果利用式(4)与式(5)将Yrr(S)修正成YNrr(S),将Ir(S)修正成INr(S),对多节点配电网络短路电流计算将会出现两种情况:(1)按局部节点等值方程编计算资讯分类行业动态帮助文档展会专题报道5金人物商家文章